You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Finding Friction's Magnitude

A boy of mass...

Question

A boy of mass 40 kg is climbing a vertical pole at a constant speed. If the coefficient of friction between his palms and the pole is 0.8 and $g = 10 m s^{- 2}$ , the horizontal force that he is applying on the pole is

300 N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

400 N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

500 N

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

600 N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
500 N

As the boy is climbing the pole at a constant speed (no acceleration), the force of friction must be just balanced by his weight, i.e.,
$μ R = m g \Rightarrow R = \frac{m g}{μ} = \frac{40 \times 10}{0.8} = 500 N$ .
Hence, the correct choice is (c).

Suggest Corrections

Similar questions

Q. A boy of mass

40

kg is climbing a vertical pole at a constant speed if the coefficient of friction between his palms and the pole is

0.8

and

g = m / s^{2}

. The horizontal force that he is applying on the pole is:

Q. A boy of mass 40 kg is climbing a vertical pole at a constant speed. If the coefficient of friction between his palms and the pole is 0.8 and g=10

m s^{- 2}

, the horizontal force that he is applying on the pole is:

A boy of mass m is sliding down a vertical pole by pressing it with a horizontal force $f$ . If $μ$ is the coefficient of friction between his palms and the pole, the acceleration with which he slides down will be equal to

Q. A fireman of mass

60 k g

slides down a pole. He is pressing the pole with a force of

600 N

. The coefficient of friction between the hands and the pole is

0.5

, with what acceleration will the fireman slide down

(g = 10 m / s^{2})

Q. A fireman of mass 60 kg slides down a pole. He is pressing the pole with a force of 600 N. The coefficient of friction between the hands and the pole is 0.5, with what acceleration will the fireman slide down (

g = 10 m / s^{2}

)

Join BYJU'S Learning Program

A boy of mass 40 kg is climbing a vertical pole at a constant speed. If the coefficient of friction between his palms and the pole is 0.8 and g=10 ms−2, the horizontal force that he is applying on the pole is

The correct option is C 500 N As the boy is climbing the pole at a constant speed (no acceleration), the force of friction must be just balanced by his weight, i.e., μR=mg⇒R=mgμ=40×100.8=500 N. Hence, the correct choice is (c).

A boy of mass 40 kg is climbing a vertical pole at a constant speed. If the coefficient of friction between his palms and the pole is 0.8 and $g = 10 m s^{- 2}$ , the horizontal force that he is applying on the pole is

The correct option is C
500 N

As the boy is climbing the pole at a constant speed (no acceleration), the force of friction must be just balanced by his weight, i.e.,
$μ R = m g \Rightarrow R = \frac{m g}{μ} = \frac{40 \times 10}{0.8} = 500 N$ .
Hence, the correct choice is (c).