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Question

A boy standing at the top of a tower of 30 m height drops a stone. Assuming g=10 ms2 the magnitude of velocity with which it hits the ground is
  1. 20 m/s
  2. 24.49 m/s
  3. 40 m/s
  4. 10.26 m/s


Solution

The correct option is B 24.49 m/s
Given, g=10 ms2 and h=30 m
Taking downward as positive,
Using third equation of motion, we have
v2u2=2gh
v=2gh (u=0)
        =2×10×30
        =600=24.49 ms1

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