A boy was flying a kite which was at a height of 40m just above a tree. The string was 50m long. How far away from the tree was the boy flying the kite?
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Solution

Height of Tree = 40

Distance of boy from free BC $= \sqrt{A C^{2} - A B^{2}}$
$= \sqrt{2500 - 1600}$
$= \sqrt{900} = 30 m$

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A boy was flying a kite which was at a height of 40m just above a tree. The string was 50m long. How far away from the tree was the boy flying the kite?undefinedundefinedundefinedundefined

Height of Tree = 40 Distance of boy from free BC =√AC2−AB2 =√2500−1600 =√900=30m

A boy was flying a kite which was at a height of 40m just above a tree. The string was 50m long. How far away from the tree was the boy flying the kite?
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Height of Tree = 40

Distance of boy from free BC $= \sqrt{A C^{2} - A B^{2}}$
$= \sqrt{2500 - 1600}$
$= \sqrt{900} = 30 m$