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Question

A brass sphere of mass $$0.2 kg$$ falls freely from a height of $$24 m$$ and bounces to a height of $$8 m$$ from the ground. If the  dissipated energy in this process is desorbed by the sphere the rose in its temperature is (specific heat of brass = $$ 360 J kg^{-1} k^{-1} $$ and $$g= 10 ms^{-2}$$ ).



A
0.44
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B
0.66
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C
0.77
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D
0.88
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Solution

The correct option is A $$0.44^{\circ}$$
$$\begin{array}{l} mg\left( { 24-8 } \right) =ms\Delta T \\ \Rightarrow 10\times 16=360\left( { \Delta T } \right)  \\ \Delta T=\dfrac { { 160 } }{ { 360 } } ={ 0.44^{ 0 } }C \\ Hence, \\ option\, \left( A \right) \, is\, correct\, answer \end{array}$$


Physics

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