Question

A broadcasting station transmits waves of frequency $71\times {10}^{4}Hz$ with speed of $3\times {10}^{8}m/s$. The wavelength of the wave is :

• A. 418.8 m
• B. 324.6 m
• C. 208.4 m
• D. 422.5 m

Answer 1

The correct option is D 422.5 m

We have, $v=n\lambda$ ,

where $v=$ speed of the wave ,

$n=$ frequency of the wave ,

$\lambda =$ wavelength of the wave ,

given $n=71\times {10}^{4}Hz,v=3\times {10}^{8}m/s$ ,

therefore , $\lambda =v/n=\frac{3\times {10}^8}{71\times {10}^4}=422.5m$