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Question

A bulb is designed to operate at 12 volts constant direct current. If this bulb is connected to an alternating current source and gives same brightness. What would be the peak voltage of the source?

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Solution

E=12V(Given)LetEobethepeakvoltageofthebulb.LetRandTbetheresistanceandtemperatureoftheelectricbulb.Since,heatproducedinaresistorbypassingAlternatingcurrentissameasheatproducedbydirectcurrentinaresistorinsametime.So,i2RT=i2rmsRT=>E2R2RT=E2rmsR2RT=>E2=E2o2(Asweknow,Erms=Eo2)=>E2o=2E2=2×122=>Eo=2×122=122=16.97V=17V

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