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Question

A bullet cart system have total mass 50m Where ′m′ is mass of each bullet. If bullet fired with velocity vm/sec with respect to cart then, find velocity of cart system after second shot.

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Solution

Applying the conservation of momentum after first shot, we get

0+0=mv+49mv′

v′=−v49m/s

Now, the initial momentum of cart before the second shot is 49mv′.

Applying the conservation of momentum after the second shot, we get

0+49mv′=mv+48mv′′

49(−v49)=mv+48mv′′

v′′=−v24m/s

Thus, the velocity of cart after the second shot is v24m/s.

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