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Question

A bullet fired into a fixed target loses half of its velocity after penetrating 3 cm. How much further it will penetrate before coming to rest assuming that it faces constant resistance to motion?


Solution

The correct option is B
Let initial velocity of the bullet = u
After penetrating 3 cm its velocity becomes u2
From v2=u22as
(u2)2=u22a(3)

6a=3u24a=u28
Let further it will penetrate through distance x and stops at point C.
For distance BC, v=0,u=u2.s=x.a=u28
From v2=u22as0=(u2)22(u28).xx=1cm.

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