Question

# A bullet fired into a fixed target loses half of its velocity after penetrating 3 cm . How much further it will penetrate before coming to rest assuming that it faces constant resistance to motion?

A
1.5 cm
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B
1.0 cm
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C
3.0 cm
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D
2.0 cm
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Solution

## The correct option is B 1.0 cm Let initial velocity of the bullet = u After penetrating 3 cm ite velocity becomes u2 From v2 = u2−2as (u2)2 = u2−2a(3) ⇒ 6a = 3u24 ⇒ a = u28 Let further it will penetrate through distance x and stops at point C. For distance BC, v = 0, u =‘u2, s = x, a = u28 From v2=u2−2as ⇒0=(u2)2−2(u28).x ⇒ x=1 cm.

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