A bullet fired into a fixed target loses half of its velocity after penetrating 3 cm . How much further it will penetrate before coming to rest assuming that it faces constant resistance to motion?
Let initial velocity of the bullet = u
After penetrating 3 cm ite velocity becomes u2
From v2 = u2−2as
(u2)2 = u2−2a(3)
⇒ 6a = 3u24 ⇒ a = u28
Let further it will penetrate through distance x and stops at point C.
For distance BC, v = 0, u =‘u2, s = x, a = u28
From v2=u2−2as ⇒0=(u2)2−2(u28).x
⇒ x=1 cm.