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Question

A bullet is dropped from the same height when another bullet is fired horizontally. They will hit the ground 


A
one after the other
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B
simultaneously
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C
depends on the observer
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D
none of these
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Solution

The correct option is B simultaneously

Time taken to reach the ground  depends on the vertical component of velocity, not horizontal component of velocity. $$u_y =0$$

$$s=u_yt + \dfrac{1}{2}gt^2=\dfrac{1}{2}gt^2$$

$$\Rightarrow t = \sqrt{\dfrac{2s}{g}}$$

Since $$s_1=s_2$$ therefore $$t_1 =t_2$$


Physics

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