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Question

A bullet is fired from a gun the force on the bullet is given by F=6002×105t where F is in newton and t in second. The force on the bullet becomes zero as soon as it leaves the barrel. What is the average impulse imparted to the bullet?

A
9 Ns
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B
Zero
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C
0.9 Ns
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D
1.8 Ns
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Solution

The correct option is C 0.9 Ns
From given question

At F = 0

6002×105t=0

t=3×103s

J=Fdt

=600t[2×105×t22]

at t=3×103

J=0.9Ns

Hence [c] option is correct

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