Question

A bullet is fired with a velocity of $196m{s}^{-1}$ at an angle ${30}^{\circ }$ with the horizontal. Calculate the maximum height attained by the bullet. (Take $g=9.8m/s^2)$

• A. $980m$
• B. $490m$
• C. $245m$
• D. $200m$

Answer 1

The correct option is B $490m$

Maximum height attained by a projectile is given by
$H=\frac{u^2{\sin }^2\theta }{2g}\Rightarrow H=\frac{{196}^2\times {\sin }^2{30}^{\circ }}{2\times 9.8}$
$=\frac{196\times 196}{8\times 9.8}$
$=490m$