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Question

A bullet loses 120 of its velocity in passing through a plank. The least number of planks required to stop the bullet is



A

10

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B

11

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C

12

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D

13

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Solution

The correct option is D

11


Let length of plank be ‘L’

Now, v2u2=2as

(19u20)2u2=2aL    2aL=39400u2 (i)

For stopping the bullet, the final velocity of the bullet will be zero

02u2=2anL         

From eq. (i), substitute the value of acceleration here, we'll get

n=10.26

which means that we will need more than 10 planks to stop the bullet and as the answer should be in whole number, we need 11 of them.


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