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Question

# A bullet moving at 250 m/s penetrates 5 cm into a tree limb before coming to rest. Assuming that the force exerted by the tree limb is uniform, find its magnitude. Mass of the bullet is 10 g.

A
625 N
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B
6250 N
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C
62.50 N
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D
6.250 N
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Solution

## The correct option is B 6250 NGiven,m=10g=0.01kgu=250m/ss=5cm=0.05mv=0m/s3rd equation of motion,v2−u2=2as02−(250)2=2×0.05×aa=625000.1=−625000m/s2The magnitude of force exterted by the tree limb is,F=maF=0.01×625000=6250NThe correct option is B.

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