A bullet of 10 g strikes a sand-bag at a speed of $10^{3} m s^{- 1}$ and gets embedded after travelling 5 cm. Then the time taken by the bullet to come to rest is :

10

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10^{2}

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10^{- 2}

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10^{- 4}

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Solution

The correct option is D $10^{- 4}$ s
$v^{2} = u^{2} + 2 a s$
$0 = (10^{3})^{2} + 2 \times a \times (5 \times 10^{- 2})$
$a = - 10^{7} m / s^{2}$

$v = u + a t$
$0 = 10^{3} - 10^{7} \times t$
$t = 10^{- 4} s$

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Similar questions

Q. A bullet of 10 g strikes sand-bag at a speed of

10^{3} m / s

and gets embedded after travelling 5 cm. Calculate

(i) the resistive force exerted by the sand on the bullet
(ii) the time taken by the bullet to come

A bullet of 10 g strikes a sand bag at a speed of 1000 m/s and gets embedded after travelling 5 cm.
Calculate a) the resistive force exerted by the sand on the bullet.
b) the time taken by the bullet to come to rest.

Question 18
Using second law of motion, derive the relation between force and acceleration. A bullet of 10 g strikes sand-bag at a speed of $10^{3} m s^{- 1}$ and gets embedded after travelling 5 cm. Calculate

(i) the resistive force exerted by the sand on the bullet
(ii) the time taken by the bullet to come

Q. A bullet of 10g strikes on a sand bag with speed of 1000m/s and stop after travelling 5cm inside the bag. Calculate :-

a) The resistive force exerted by the sand on the bullet
b) The time taken by the bullet to come to rest.

Q. A bullet of

10 g

strikes sand-bag at a speed of

10^{3} m / s

and comes to stop after travelling 5 cm. Calculate:
(i) The resistive force exerted by the sand on the bullet.
(ii) Time of collision.

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A bullet of 10 g strikes a sand-bag at a speed of 103 ms−1 and gets embedded after travelling 5 cm. Then the time taken by the bullet to come to rest is :

The correct option is D 10−4 sv2=u2+2as0=(103)2+2×a×(5×10−2)a=−107 m/s2v=u+at0=103−107×tt=10−4 s

A bullet of 10 g strikes a sand-bag at a speed of $10^{3} m s^{- 1}$ and gets embedded after travelling 5 cm. Then the time taken by the bullet to come to rest is :

The correct option is D $10^{- 4}$ s
$v^{2} = u^{2} + 2 a s$
$0 = (10^{3})^{2} + 2 \times a \times (5 \times 10^{- 2})$
$a = - 10^{7} m / s^{2}$

$v = u + a t$
$0 = 10^{3} - 10^{7} \times t$
$t = 10^{- 4} s$