CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

A bullet of 5 g is fired from a pistol of 1.5 kg. If the recoil velocity of pistol is 1.5 ms, find the velocity of bullet. (in ms)


  1. 450 ms

  2. 500 ms

  3. 600 ms

  4. 400 ms


Solution

The correct option is A

450 ms


Here, we have,

Mass of bullet, m1=5 g =51000 kg =0.005 kg

Mass of pistol, m2=1.5 kg

Recoil velocity of pistol \(v_2 = 1.5\) m/s

We have to find the velocity of the bullet, v1.

Since, before firing, the bullet and pistol are in rest, thus

Initial velocity of bullet, u1=0

And initial recoil velocity of pistol, u2=0

We know that,

\(m_1 u_1+m_2 ​​u_2​​​​​​​ = m_1 v_1​​​​​​​+m_2 v_2\)​​​​​​​

0.005×0+1.5×0=0.005×v1+1.5×1.5 ms)

0=0.005×v1+2.25 kgms

0.005×v1=2.25 kgms

v1=2.250.005=450 ms

Thus, the velocity of bullet =450 ms, here negative sign shows that, bullet moves in the opposite direction of recoiling of the gun.

flag
 Suggest corrections
thumbs-up
 
0 Upvotes


Similar questions
QuestionImage
QuestionImage
View More...


People also searched for
QuestionImage
QuestionImage
View More...



footer-image