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Question

A bullet of 5 g is fired from a pistol of 1.5 kg. If the recoil speed of pistol is 1.5 ms1, find the velocity of bullet.


A

450 ms1

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B
400 ms1
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C
500 ms1
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D
600 ms1
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Solution

The correct option is A

450 ms1


Given:
Mass of the bullet:
m1=5g=5×103 kg
Mass of the pistol, m2=1.5 kg
Recoil speed of the pistol, v2=1.5 ms1

Let the velocity of the bullet be v1

Before firing, the bullet and pistol are in rest. Hence,
Initial speed of bullet, u1=0
Initial speed of pistol, u2 = 0

From law of conservation of momentum, initial and final momentums are equal.
m1u1+m2u2=m1v1+m2v2
0=(5×103×v1)+(1.5×1.5)
v1=450 ms1

Thus, speed of the bullet is 450 ms1.
Negative sign shows that bullet moves in the direction opposite to the direction of recoiling of the gun.


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