A bullet of mass 20 gm is fired from a rifle of mass 20 kg with a muzzle velocity of $200 m s^{- 1}$ . Find the velocity of recoil of the rifle.

0.4 m s^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.5 m s^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.2 m s^{- 1}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

0.3 m s^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $0.2 m s^{- 1}$
By the law of conservation of momentum,
Initial momentum $=$ find momentum
$∴ P_{1} = P_{2}$
$∴ m_{1} v_{1} = m_{2} v_{2}$
here, $m_{1} = 20 g m . v_{1} = 200 m s^{- 1}, m_{2} = 20 k g = 20, 000 g m$

$∴ v_{2} = \frac{m_{1} v_{1}}{m_{2}}$

$= \frac{20 \times 200}{20, 000}$

$∴ v_{2} = 0.2 m / s$

$∴$ option (c) is correct.

Suggest Corrections

Similar questions

From a rifle of mass 4 kg, a bullet of mass 50 g is fired with a velocity of $35 m s^{- 1}$ .The recoil velocity of the rifle is:

500 m s^{- 1}

5 m s^{- 1}

20 g

5 kg

180 {m s}^{- 1}

{m s}^{- 1}

5 k g

40 g

200 m s^{- 1}

0.004 s

From a rifle of mass 4 kg, a bullet of mass 50 g is fired with an initial velocity of 35 m s⁻¹. Calculate the initial recoil velocity of the rifle.