A bullet of mass ' $a$ ' and velocity ' $b$ ' is fired into a large wood of mass ' $c$ '. The final velocity of the system is:

\frac{a b}{a + c}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{b}{c} (a + c)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{c b}{(a + b)}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{b}{c} (a + b)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $\frac{a b}{a + c}$
Here, a bullet of mass ' $a$ ' and velocity ' $b$ ' is fired into a large wood of mass ' $c$ '. We can write,
$m_{1} u_{1} + m_{2} u_{2} = (m_{1} + m_{2}) v$
$a b + c (0) = (a + c) v$
$a b = (a + c) v$
$\Rightarrow v = \frac{a b}{a + c}$

Suggest Corrections

Similar questions

Q. A bullet of mass a and velocity b is fired into a large block of wood of mass c. The final velocity of the system is

Q. A bullet of mass a and velocity b is fired into a large block of mass c. the final velocity of the system is

Q. A bullet of mass

A

and velocity

B

is fired into a block of wood of mass

C

. If loss of any mass and friction be neglected, the velocity of the system must be

Q. A bullet of mass m and velocity v is fired into a large block of wood of mass M . The final velocity of the system is :

A bullet of mass A and velocity B is fired into a wooden block of mass C. If the bullet gets embedded in the wooden block, then the the magnitude of velocity of the system just after collision will be

(a)A+B/AC . (b)A+C/B+C . (c)AC/B+C . (d)AB/A+C

Join BYJU'S Learning Program

A bullet of mass 'a' and velocity 'b' is fired into a large wood of mass 'c'. The final velocity of the system is:

The correct option is C aba+cHere, a bullet of mass 'a' and velocity 'b' is fired into a large wood of mass 'c'. We can write, m1u1+m2u2=(m1+m2)vab+c(0)=(a+c)vab=(a+c)v ⇒v=aba+c

A bullet of mass ' $a$ ' and velocity ' $b$ ' is fired into a large wood of mass ' $c$ '. The final velocity of the system is:

The correct option is C $\frac{a b}{a + c}$
Here, a bullet of mass ' $a$ ' and velocity ' $b$ ' is fired into a large wood of mass ' $c$ '. We can write,
$m_{1} u_{1} + m_{2} u_{2} = (m_{1} + m_{2}) v$
$a b + c (0) = (a + c) v$
$a b = (a + c) v$
$\Rightarrow v = \frac{a b}{a + c}$