Question

A bullet of mass $$m$$ is fired with a velocity $$v$$ into a fixed log of wood and penetrates a distance s before coming to rest. Assuming that the path of the bullet in the log of wood is horizontal, the average resistance offered by the log of wood is

A
mv2s2
B
mv22s
C
2smv2
D
ms22v

Solution

The correct option is B $$\dfrac{mv^{2}}{2s}$$W.D resistance $$=\Delta K.E$$$$\vec{F}.\vec{S}=\dfrac{1}{2}mv^{2}_{final}-\dfrac{1}{2}mu^{2}_{initial}$$$$\vec{F}.\vec{S}=-\dfrac{1}{2}mv^{2}$$$$\Rightarrow -F.s=-\dfrac{1}{2}mv^{2}$$$$\Rightarrow F=\dfrac{mv^{2}}{2s}$$Physics

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