MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Time Period Independent of Amplitude

a bullet of m...

Question

a bullet of mass m passes through a pendulum of mass M with velocity v and come out of it with a velocity v /2 .the minimum value of v so that the bob complete it's one revolution in the vertical circle is ( l is length of pendulum )

Open in App

Solution

Suggest Corrections

thumbs-up

5

Similar questions

Q. A bullet of mass m and velocity v passes through a pendulum of mass M and emerges with velocity

v / 2

. What is the minimum value of

v

such that the pendulum will swing through a complete cycle?

Q. A pendulum consists of a wooden bob of mass m and length

l

. A bullet of mass

m_{1}

is fired towards the pendulum with a speed

v_{1}

. The bullet emerges out of the bob with a speed of

v_{1} / 3

and the bob just complete motion along a vertical circle, then

v_{1}

Q. The length of simple pendulum is 1 m and mass of its bob is 50 g. The bob is given sufficient velocity so that the bob describe vertical circle whose radius equal to length of pendulum. The maximum difference in the kinetic energy of bob during one revolution is.

Q. A pendulum bob of mass

10 g

is attached to a rod of length

2 m

and is allowed to move in the vertical circle. Find the minimum velocity of bob at the bottom of the circle so that the bob completes the circle.
(Take

g = 10 m / s^{2}

)

Q. A pendulum consists of a wooden bob of mass m and of length

l

. A bullet of mass

m_{1}

is fired towards the pendulum with a speed

v_{1}

. The bullet emerges out of the bob with a speed

v_{1} / 3

and the bob just completes motion along a vertical circle. Then

v_{1}

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Simple Harmonic Oscillation

PHYSICS

Watch in App

explore_more_icon

Explore more

Time Period Independent of Amplitude

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon