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Question

A bullet when fired into a target loses half of its velocity after penetrating 20 cm. Further distance of penetration before it comes to rest is :

A
6.66 cm
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B
3.33 cm
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C
12.5 cm
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D
10 cm
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E
5 cm
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Solution

The correct option is B 6.66 cm
Given, Initial velocity, U=v
Final velocity, V=v2
Distance, s=20cm

Let, the further distance of penetration before it comes to rest be x.
V2=U22as
(V2)2=V22a×20
40a=V2V24
40a=3V24 ...(i)

and V2=u2+2as
v2=0+2a×(20+x)
v2=2×3160v2×(20+x) [From Eq. (i)]
1=380(20+x)
803=20+x
x=80320
x=80603
x=203=6.66cm

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