A bus accelerates uniformly from 54 km/h to 72 km/h in 10 seconds Calculate acceleration

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Solution

$D e a r S t u d e n t, G i v e n, u = 54 k m / h = 54 \times \frac{1000}{3600} m / s = 54 \times \frac{5}{18} = 15 m / s v = 72 k m / h = 72 \times \frac{5}{18} = 20 m / s, t = 10 s v = u + a t A c c e l e r a t i o n i s, a = \frac{v - u}{t} = \frac{20 - 15}{10} = 0.5 m / s^{2} R e g a r d s$

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A bus accelerates uniformly from 54 km/h to 72 km/h in 10 seconds Calculate acceleration

Dear Student,Given,u=54km/h=54×10003600m/s=54×518=15m/sv=72km/h=72×518=20m/s,t=10sv=u+atAcceleration is,a=v-ut=20-1510=0.5m/s2Regards

$D e a r S t u d e n t, G i v e n, u = 54 k m / h = 54 \times \frac{1000}{3600} m / s = 54 \times \frac{5}{18} = 15 m / s v = 72 k m / h = 72 \times \frac{5}{18} = 20 m / s, t = 10 s v = u + a t A c c e l e r a t i o n i s, a = \frac{v - u}{t} = \frac{20 - 15}{10} = 0.5 m / s^{2} R e g a r d s$