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Question

A bus accelerates uniformly from 54km/hr to 72km/hr in 10s. Calculate the distance covered by the bus in metres during interval and also find the acceleration in metre per second square.


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Solution

Step 1: Given

Initial velocity, u=54km/hr=15m/s

Final velocity, v=72km/hr=20m/s

Time, t=10s

Step 2: Calculate the acceleration

Using first equation of motion,

a=v-ut=20-1510=0.5m/s2

Step 3: Calculate the distance traveled by bus

Using the third equation of motion, the distance s can be calculated

v2=u2+2as202=152+2(0.5)ss=202-1522(0.5)s=175m

Therefore, the distance covered is 175m and the acceleration is 0.5m/s2


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