A bus accelerates uniformly from rest and acquires a speed of $75 k m / h r$ in $20 s$ . The acceleration of the bus (rounded off to the nearest integer) is:

10 m / s^{2}

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5 m / s^{2}

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2 m / s^{2}

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1 m / s^{2}

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Solution

The correct option is C $1 m / s^{2}$
$v = u + a t$
$v = 75 \frac{k m}{h r} = \frac{75 \times 1000}{3600} (\frac{m}{s})$
$u = 0, t = 20 s e c$
$a = \frac{75 \times 1000}{3600} \times \frac{1}{20} = 1.04 m / s^{2}$

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A bus accelerates uniformly from rest and acquires a speed of 75 km/hr in 20 s. The acceleration of the bus (rounded off to the nearest integer) is:

The correct option is C 1 m/s2v=u+atv=75kmhr=75×10003600(ms)u=0,t=20seca=75×10003600×120=1.04m/s2

A bus accelerates uniformly from rest and acquires a speed of $75 k m / h r$ in $20 s$ . The acceleration of the bus (rounded off to the nearest integer) is:

The correct option is C $1 m / s^{2}$
$v = u + a t$
$v = 75 \frac{k m}{h r} = \frac{75 \times 1000}{3600} (\frac{m}{s})$
$u = 0, t = 20 s e c$
$a = \frac{75 \times 1000}{3600} \times \frac{1}{20} = 1.04 m / s^{2}$