Question

a bus starting from rest attains a speed of 36 km per hour in 5 seconds calculate acceleration and distance travel by bus during this duration

Answer 1

Dear Student,

$$\begin{gathered} \mathrm{initial}\mathrm{velocity},\mathrm{u}=0 \\ \mathrm{final}\mathrm{velocity},\mathrm{v}=36\mathrm{km}/\mathrm{h} \\ \mathrm{v}=36\times \frac{5}{18}\mathrm{m}/\mathrm{s}=10\mathrm{m}/\mathrm{s} \\ \mathrm{time},\mathrm{t}=5\mathrm{s} \\ \mathrm{v}=\mathrm{u}+\mathrm{at} \\ 10=0+\mathrm{a}\times 5 \\ \mathrm{a}=2\mathrm{m}/{\mathrm{s}}^2 \\ {\mathrm{v}}^2-{\mathrm{u}}^2=2\mathrm{as} \\ {10}^2-0^2=2\times 2\mathrm{s} \\ \mathrm{s}=\frac{100}{4}=25\mathrm{m} \end{gathered}$$