A bus starts from rest and acuquires the velocity of 54km/h in 2 mins. Find the acceleration and the distance travelled by bus during this time.

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Solution

Dear Student
9 $I n i t i a l v e l o c i t y = 0 f i n a l v e l o c i t y = 54 \times \frac{5}{18} = 15 m / s e c t i m e = 2 \times 60 = 120 s e c v = u + a t 15 = a \times 120 a = 0.125 m s^{- 2} S = u t + \frac{1}{2} a t^{2} S = \frac{1}{2} \times 0.125 \times 120 \times 120 = 900 m R E G A R D S$

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A bus starts from rest and acuquires the velocity of 54km/h in 2 mins. Find the acceleration and the distance travelled by bus during this time.

Dear Student 9Initial velocity=0final velocity=54×518=15m/sectime=2×60=120secv=u+at15=a×120a=0.125ms-2S=ut+12at2S=12×0.125×120×120=900mREGARDS