Question

(a) Calculate the heat capacity of a copper vessel of mass 150 g if the specific heat capacity of copper is 410 J $k{g}^{-1}{K}^{-1}$.

(b) How much heat energy will be required to increase the temperature of the vessel in part(a) from 25${}^{\circ }Cto{35}^{\circ }C$?

Answer 1

(i) Heat capacity = Mass × Specifc heat capacity
= $150\times {10}^{-}3kg\times 410J/\left(kgK\right)$
= 61.5 J / K
The heat capacity of copper is 61.5 J/K

(ii) Q=m⋅c⋅ΔT ,

where; Q - heat absorbed
m - the mass of the sample
c - the specific heat of the substance
ΔT - the change in temperature, defined as final temperature minus initial temperature

ΔT = ${35}^o-{25}^o$ = ${10}^o$

Q = $150\times {10}^{-}3\times 410\times 10$

Q = 615 J