Question

# A can do a piece of work in 24 days. If B is 60% more efficient then the number of days required by B to do the twice as large as the earlier work is-

A
24
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B
36
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C
15
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D
30
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Solution

## The correct option is D 30According to the question-A can do a piece of work in 24 days.∴ work done by A in 1 day =124Given that, B is 60% more efficient, i.e., B can do 60% more work than work done by A in 1 day-Work done by B in 1 day =124+60100×124=115∴ number of days required by B to do the same work =15days∴ number of days required by B to do the twice as large as the earlier work =2×15=30 days

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