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Question

A capacitor has capacitance of 6 nF, maximum voltage it can sustain is 40 volt. It is in series with other capacitor 3 nF and this capacitor can sustain 30 volt, what is maximum voltage that can be applied in series.

A
70
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B
50
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C
60
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D
10
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Solution

The correct option is C 60

qsupplied=Ceff ϵ=(C1C2C1+C2) ϵ

ΔV1=qC1=C2ϵC1+C2=6ϵ9=2ϵ3

(C1=6C2=3)

ΔV2=qC2=C1ϵC1+C2=3ϵ9=ϵ3

ΔV1<40ΔV2<302ϵ3<40ϵ3<30ϵ<60ϵ<90ϵ<90

ϵmax=60

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