Question

# A capillary tube of radius R is immersed in water and water rises in it to a height H. Mass of water in the capillary tube is M, If the radius of the tube is doubled mass of water that will rise in capillary tube water be

A
2M
B
M
C
M2
D
4M

Solution

## The correct option is A 2MMass of water in capillary rise $$= Ah\rho$$$$A=$$ area of cross-section, $$h=$$ height, $$\rho =$$ density$$\Rightarrow m = (\pi r^2)h\rho = \pi r^2 \times \dfrac{2\sigma \cos\theta}{r\rho g}$$$$\Rightarrow m \propto r$$$$\therefore$$ Doubling radius $$\Rightarrow$$mass will also get doubled$$m'=2 M$$Physics

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