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Question

A capillary tube of radius r is immersed vertically in a liquid such that liquid rises in it to height h (less than the length of the tube). Mass of liquid in the capillary tube is m. If radius of the capillary tube is increased by 50%, then mass of liquid that will rise in the tube, is

A
23m
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B
m
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C
32m
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D
94m
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Solution

The correct option is C 32m
h=2Tcosθrρgh1rh2h1=r1r2=23
(r1=r,r2=r+50% of r=32r)
New mass m2=πr22h2ρ=π(32r1)2(23h1)ρ
=32(πr21h1)ρ=32m

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