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Question

A car accelerates uniformly from 18km/hr to 36km/hr in 5s. Calculate the acceleration and the distance covered by the car in that time.


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Solution

Step 1: Given

Initial velocity, u=18km/hr=5m/s

Final velocity, v=36km/hr=10m/s

Time, t=5s

Step 2: Formula used

  1. The first equation of motion is given as,v=u+at
  2. The second equation of motion is given as, s=ut+12at2

Step 3: Determine the acceleration

Using the first equation of motion,

v=u+at10=5+a(5)a=1m/s2

Step 4: Determine the distance covered

Using the second equation of motion, determine the distance s.

s=ut+12at2=5(5)+12(1)(5)2=37.5m

Therefore, the acceleration and the distance covered by the car in that time are 1m/s2 and 37.5m respectively.


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