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Question

A car approaching a school zone slows down from 27m/s to 9m/s with constant acceleration −2m/s2. How much time is required to slow down to final velocity?


A
3s
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B
6s
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C
9s
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D

12s

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Solution

The correct option is C 9s

We know initial velocity u=27m/s, final velocity v=9m/s and acceleration a=2m/s2

As we kinow, v=u+at
or, vu=at
or, t=vua

Putting the values in above equation, we get,
t=9m/s27m/s2ms2
or, t=18m/s2ms2
or, t=9s


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