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Question

A car at rest starts moving with uniform acceleration of 10 ms−2 for a time of 10 seconds. What is the distance covered by the car?

A
100 m
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B
500 m
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C
200 m
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D
600 m
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Solution

The correct option is B 500 m
Given, initial velocity, u = 0 ( the car is initially at rest)
time taken, t=10s
acceleration, a=10 ms2

Let the distance covered be 's'.

From the second equation of motion,
s=ut+12×at2
s=(0×10)+(12×10×102)
s=10002 = 500 m
The distance covered by the car is 500 m.



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