A car is accelerated on a levelled road and attains a speed of 4 times its initial speed. In this process, the kinetic energy of the car :

(a) does not change

(b) becomes 4 times that of initial kinetic energy

(c) becomes 8 times that of initial kinetic energy

(d) becomes 16 times that of initial kinetic energy

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Solution

(d) becomes 16 times that of initial kinetic energy

$K . E . = \frac{1}{2} m v^{2}$
so
K.E. is proportional to $v^{2}$ i.e., the kinetic energy of the car becomes 16 times that of initial kinetic energy

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Similar questions

A car is accelerated on a levelled road and acquires a velocity 4 times of its initial velocity. During this process, the potential energy of the car :

(a) does not change

(b) becomes twice that of initial potential energy

(d) becomes 16 times that of initial potential energy

Q. Question 2
A car is accelerated on a leveled road and attains a velocity 4 times of its initial velocity. In this process the potential energy of the car

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(d) becomes 16 times that of initial kinetic energy K.E.=12mv2 so K.E. is proportional to v2 i.e., the kinetic energy of the car becomes 16 times that of initial kinetic energy

(d) becomes 16 times that of initial kinetic energy

$K . E . = \frac{1}{2} m v^{2}$
so
K.E. is proportional to $v^{2}$ i.e., the kinetic energy of the car becomes 16 times that of initial kinetic energy