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Question

A car is moving with constant speed on a road as shown in figure. The normal reaction by the road on the car is NA,NB and NC when it is at the points A, B and C respectively. Then:


  1. NA=NB
  2. NA<NB
  3. NA=NC
  4. NA>NB


Solution

The correct option is D NA>NB
Let us suppose constant speed of car is u and mass is m.


Car is in vertical equilibrium in each case. Hence Fy=0
Case - 1) when car is at point A 
mgNA=mu2RA
NA=mgmu2RA(1)

Case - 2) when car is at point B
NB=mgmu2RB(2)

Case - 3) when car is at point C 
NC=mgmu2RC(3)

From diagram, we can see that
RC>RA>RB
mu2RC<mu2RA<mu2RB
mgmu2RC>mgmu2RA>mgmu2RB
NC>NA>NB
[from equation 1, 2 & 3]
Normal Reaction at point A is greater than at point B. 

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