Question

A car is travelling along the road at 8 m s⁻¹. It accelerates at 1 m s⁻² for a distance of 18 m. How fast is it then travelling?

Answer 1

We have to find the final velocity of the moving object. And we have the following information
Initial velocity, (u) = 8 m/s
Acceleration, (a) = 1 m/s²
Distance, (s) = 18 m
So applying 3^rd equation of motion to calculate the final velocity,
$\nu =\sqrt{u^2+2as}$
Where,
(a) - Acceleration
(ν) - Final velocity
(u) - Initial velocity
(s) - Distance
Put the values in the above equation to get the value of final velocity,
$$\begin{gathered} \nu =\sqrt{64+36}\mathrm{m}/\mathrm{s} \\ =\sqrt{100}\mathrm{m}/\mathrm{s} \\ =\boxed{10\mathrm{m}/\mathrm{s}} \end{gathered}$$