A car moves with a speed of $30 k m / h^{- 1}$ for half an hour,for $25 k m / h^{- 1}$ one hour and $40 k m / h^{- 1}$ for two hours.Calculates the average speed

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Solution

Average speed = $\frac{t o t a l d i s t a n c e}{t o t a l t i m e}$
The distance covered= $30 \times \frac{1}{2} + 25 \times 1 + 40 \times 2 = 120 k m$
Time taken= $0.5 + 1 + 2 = 3.5 h$
Hence,
Average speed= $\frac{120}{3.5} = 34.286 k m / h$

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A car moves with a speed of 30km/h−1 for half an hour,for 25km/h−1 one hour and 40km/h−1 for two hours.Calculates the average speed

Average speed =totaldistancetotaltimeThe distance covered=30×12+25×1+40×2=120kmTime taken=0.5+1+2=3.5hHence,Average speed=1203.5=34.286km/h

A car moves with a speed of $30 k m / h^{- 1}$ for half an hour,for $25 k m / h^{- 1}$ one hour and $40 k m / h^{- 1}$ for two hours.Calculates the average speed

Average speed = $\frac{t o t a l d i s t a n c e}{t o t a l t i m e}$
The distance covered= $30 \times \frac{1}{2} + 25 \times 1 + 40 \times 2 = 120 k m$
Time taken= $0.5 + 1 + 2 = 3.5 h$
Hence,
Average speed= $\frac{120}{3.5} = 34.286 k m / h$