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Question

A car moving along a straight highway with speed of 126km/hr is brought to a stop within a distance of 200m. What is the retardation of the car and how long does it take for the car to stop?


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Solution

Step 1: Given

Speed of the car, u=126km/hr=35m/s

Final speed of the car, v=0

Distance, s=200m

Step 2: Determine the acceleration a

Using the third equation of motion,

v2=u2+2as02=352+2(a)(200)a=-352400=-3.065m/s2

Negative acceleration suggests retardation.

Step 3: Determine the time taken

Using the first equation of motion,

v=u+at0=35+(-3.065)tt=11.4s

Therefore, The retardation of the car is -3.065m/s2 and it takes the car 11.4s to stop.


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