Question

# A car moving with a velocity of $$10 m/s$$ can be stopped by the application of a constant force F in a distance of $$20m$$. If the velocity of the car is $$30m/s$$. It can be stopped by this force in:-

A
203m
B
20m
C
60m
D
180m

Solution

## The correct option is D $$180m$$Final velocity is zero.and acceleration is $$-ve$$$$0=u^2-2\times a\times s \\s=\dfrac { { u }^{ 2 } }{ 2a } \\ s\propto { u }^{ 2 }$$if car moving with a velocity of $$10 m/s$$ can be stopped by the application of a constant force F in a distance of $$20m$$, since the velocity is tripled stopping distance will become $$3^2 = 9$$times.New stopping distance $$= 9*20= 180 m$$Physics

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