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Question

A car moving with a velocity of $$10 m/s$$ can be stopped by the application of a constant force F in a distance of $$20m$$. If the velocity of the car is $$30m/s$$. It can be stopped by this force in:-


A
203m
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B
20m
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C
60m
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D
180m
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Solution

The correct option is D $$180m$$
Final velocity is zero.and acceleration is $$-ve$$
$$0=u^2-2\times a\times s \\s=\dfrac { { u }^{ 2 } }{ 2a } \\ s\propto { u }^{ 2 }$$
if car moving with a velocity of $$10 m/s$$ can be stopped by the application of a constant force F in a distance of $$20m$$, since the velocity is tripled stopping distance will become $$3^2  =  9 $$times.

New stopping distance $$= 9*20= 180 m$$

Physics

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