Question

A car starts from rest and has an acceleration $a=1m/s^2$.A truck is moving with a uniform velocity of $6m/s$. At what distance will the car overtake the truck? direction (at $t=0$ both start their motion in the same direction from the same position)

• A. 36 m
• B. 8 m
• C. 32 m
• D. 4 m

Answer 1

Answer: (A)

36 m

At the $moment$ when the car will be $overtaking$ the truck their $velocitis$ will be $same.$

so suppose after $t$ second from the start of the motion the car overtake the truck then the velocity of the car at that moment will be $v=0+at=t\times 1m/s^2=t$ $m/s$

and the velocity of the truck at that moment will be $u=6m/s\left(constant\right)$

both should be same i.e $u=v$ or $6=t$ or $t=6$ $second$

so the distance covered by truck $\text{oe car because both will be at same place ast that point of time}$ in this time

will be $s=vt=6\times 6=36meter$