A car travel a distance $100 m$ with a constant acceleration and average velocity of $20 m / s$ . The final velocity acquired by the car is $25 m / s$ . Find: acceleration of car.

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Solution

Given: $v = 25 m / s; s = 100 m$ ; average velocity $= 20 m / s$
$v^{2} - u^{2} = 2 a S$
$(25)^{2} - (15)^{2} = 2 \times a \times 100$
$625 - 225 = 200 a$
$a = 2 m / s^{2}$

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A car travel a distance 100 m with a constant acceleration and average velocity of 20 m/s. The final velocity acquired by the car is 25 m/s. Find: acceleration of car.

Given: v=25 m/s;s=100 m; average velocity =20 m/sv2−u2=2aS(25)2−(15)2=2×a×100625−225=200aa=2 m/s2

A car travel a distance $100 m$ with a constant acceleration and average velocity of $20 m / s$ . The final velocity acquired by the car is $25 m / s$ . Find: acceleration of car.

Given: $v = 25 m / s; s = 100 m$ ; average velocity $= 20 m / s$
$v^{2} - u^{2} = 2 a S$
$(25)^{2} - (15)^{2} = 2 \times a \times 100$
$625 - 225 = 200 a$
$a = 2 m / s^{2}$