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Question

A car traveling at 22.4m/s skids to a stop in 2.55s. Determine the skidding distance of the car (assume uniform acceleration).

A
28.6m
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B
286m
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C
276m
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D
27.6m
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Solution

The correct option is D 28.6m
Here, initial velocity, u=22.4m/s and final velocity, v=0 m/s
Time taken by car to stop t=2.55s
If a be the acceleration.
Using formula v=u+at,
0=22.4+a(2.55)
We get a=8.78m/s2 (negative signs means deceleration of car)
If d be the distance traveled by car.
Using formula v2u2=2ad
02(22.4)2=2(8.78)d
d=28.6m

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