A carbon resistor of $(47 \pm 4.7) k Ω$ is to be marked with rings of different colours for its identification. The colour code sequence will be:

Yellow-Green-Violet-Gold

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Violet-Yellow-Orange-Silver

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Green-Orange-Violet-Gold

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Yellow-Violet-Orange-Silver

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Solution

The correct option is D Yellow-Violet-Orange-Silver

Digit Multiplier Tolerance
4 7 $10^{3}$ $\frac{4.7}{47} = 10$ %
Yellow - Violet - Orange - Silver

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A carbon resistor of (47±4.7)kΩ is to be marked with rings of different colours for its identification. The colour code sequence will be:

The correct option is D Yellow-Violet-Orange-Silver Digit Multiplier Tolerance 4 7 103 4.747=10%Yellow - Violet - Orange - Silver

A carbon resistor of $(47 \pm 4.7) k Ω$ is to be marked with rings of different colours for its identification. The colour code sequence will be:

The correct option is D Yellow-Violet-Orange-Silver

Digit Multiplier Tolerance
4 7 $10^{3}$ $\frac{4.7}{47} = 10$ %
Yellow - Violet - Orange - Silver