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Question

A carboxylic acid ester is prepared commonly by reacting a carboxylic acid with excess of an alcohol in the presence of a small quantity of a strong acid such as conc.H2SO4 as a catalyst. The reaction is reversible and generally the equilibrium constant for the esterification is close to 1. As it is a reversible reaction, different methods are used to increase the yield of ester. It is established that the mechanism of esterification under such conditions involves initial protonation of the acid followed by the attack of the alcohol as a nucleophile.
The correct statement(s) is/are__________.

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A
When esterification is carried out using molar ratio of acid and alcohol as 1:10, the yield of the ester with respect to the acid should be close to 90%
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B
The function of conc. H2SO4 is also to increase the free energy change of the reaction and thereby increasing the equilibrium constant
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C
When an ester is heated with acidified water the protonation will be more favourable at the acyl oxygen atom than at the alkoxy oxygen atom
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D
When butyl hexanoate is heated with a large excess of methanol in the presence of a small quantity of conc. H2SO4, methyl hexanoate is the major product
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Solution

The correct options are
A When esterification is carried out using molar ratio of acid and alcohol as 1:10, the yield of the ester with respect to the acid should be close to 90%
C When an ester is heated with acidified water the protonation will be more favourable at the acyl oxygen atom than at the alkoxy oxygen atom
D When butyl hexanoate is heated with a large excess of methanol in the presence of a small quantity of conc. H2SO4, methyl hexanoate is the major product
  • 1:10 ratio of Acid and alcohol yields the ester 90%
  • H2SO4 is proton donor.
  • When ester is heated with acidified water the protonation will be more favorable at the acyl oxygen atom than at the Alkoxy atom
  • Butyl hexanate is heated with excess methanol in presence of small quantity of conc.H2SO4 gives methyl hexonate is major product.

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