A Carnot engine working between 300 K and 600 K has a work output of 800 J per cycle. The amount of heat energy supplied to the engine from the source in each cycle is

800 J

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1600 J

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3500 J

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6400 J

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Solution

The correct option is B 1600 J
$η = 1 - \frac{T_{L}}{T_{H}} \Rightarrow \frac{W}{Q_{1}} = 1 - \frac{T_{L}}{T_{H}}$

$T_{L} = 300 K T_{H} = 600 K$

$\frac{800}{Q_{1}} = 1 - \frac{1}{2} = \frac{1}{2}$

$∴ Q_{1} = 1600 J$

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A Carnot engine working between 300 K and 600 K has a work output of 800 J per cycle. The amount of heat energy supplied to the engine from the source in each cycle is

The correct option is B 1600 Jη=1−TLTH⇒WQ1=1−TLTH TL=300 KTH=600 K 800Q1=1−12=12 ∴Q1=1600 J

The correct option is B 1600 J
$η = 1 - \frac{T_{L}}{T_{H}} \Rightarrow \frac{W}{Q_{1}} = 1 - \frac{T_{L}}{T_{H}}$

$T_{L} = 300 K T_{H} = 600 K$

$\frac{800}{Q_{1}} = 1 - \frac{1}{2} = \frac{1}{2}$

$∴ Q_{1} = 1600 J$