A Cathode ray tube emits $1.875 \times 10^{3}$ electrons per second when heated. When 600 V is applied to the anode all the electrons emitted reach the anode. The maximum electron current will be

3 A

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3 μ A

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3 m A

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None of these

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Solution

The correct option is C $3 m A$
Given that number of electrons emitted per second $= 1.875 \times 10^{16}$ electrons per second.
Charge transfer $= 1.875 \times 1.618 \times 10^{16 - 19} = 3 \times 10^{- 3} C / s = 3 m A$

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A Cathode ray tube emits 1.875×103 electrons per second when heated. When 600 V is applied to the anode all the electrons emitted reach the anode. The maximum electron current will be

The correct option is C 3mAGiven that number of electrons emitted per second =1.875×1016 electrons per second.Charge transfer =1.875×1.618×1016−19=3×10−3C/s=3 mA

A Cathode ray tube emits $1.875 \times 10^{3}$ electrons per second when heated. When 600 V is applied to the anode all the electrons emitted reach the anode. The maximum electron current will be

The correct option is C $3 m A$
Given that number of electrons emitted per second $= 1.875 \times 10^{16}$ electrons per second.
Charge transfer $= 1.875 \times 1.618 \times 10^{16 - 19} = 3 \times 10^{- 3} C / s = 3 m A$