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Question

A cathode ray tube has a potential difference of V volt between the cathode and the anode. The speed of cathode rays is given by

A
6×105Vcm/s
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B
6×105Vm/s
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C
6×107Vcm/s
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D
6×103Vm/s
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Solution

The correct option is B 6×105Vm/s
The kinetic energy of electrons is
E=12mv2
The potential between cathode and anode is V hence,
12mv2=eV
v2=2eVm
v2=2×1.6×1019V9.1×1031
v2=0.35×1012V
v=35×1010V
v=5.9×105V
v6×105Vms1

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