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Question

b+ca+c f(x) dx is equal to 
  1. ba f(xc) dx
  2. ba f(x) dx
  3. ba f(x+c) dx
  4. bcac f(x) dx


Solution

The correct option is C ba f(x+c) dx
b+ca+c f(x) dxBy putting x = t + c in the given expression, we get
ba f(t+c) dt=ba f(x+c) dx
 

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